Most efficient trapezoidal section of canal

The most efficient trapezoidal section of canal can be calculated as follows

canal section.JPG
Let,
Base width of the canal=B
Side slope=m (1V:mH)
Flow depth = h
Wetted perimeter= P

The cross sectional area, A=By+my^2
ie B= (A-m*h^2)/h
ie B=A/h-m*h
Wetted perimeter P= B+2*h *sqrt(m^2+1)
For most efficient channel, dP/dh=0
ie -A-m*y^2+2 y^2 sqrt(m^2+1)=0
ie B= y(2*sqrt(m2+1)-1-m)
Therfoer B/y=2*sqrt(m2+1)-1-m is the required relationship

Post a comment or leave a trackback: Trackback URL.

Comments

  • Jonas Paul B. de la Cruz  On November 30, 2011 at 10:06 pm

    What is y?

  • Minilik  On January 29, 2014 at 5:53 pm

    It very nice i.e short and priceze

  • new age facelift  On December 23, 2014 at 1:31 am

    Have yoս ever considered writing an ebook or guest authoring
    oon օther websites? I ɦave a blog based upon on the
    same informatiօn you discuss and would love to hzve yoս share
    sօme stories/informatіοn. I know mƴ audience ѡould enjoy
    your work. If ƴߋu аre even remotely іnterested, eel free tߋ send me an е mail.

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s

Follow

Get every new post delivered to your Inbox.

%d bloggers like this: